{"version":"https://jsonfeed.org/version/1.1","title":"苏迟但到的主页","home_page_url":"https://kexohproject.pages.dev","feed_url":"https://kexohproject.pages.dev/json/","description":"<p>你好，欢迎访问个人主页！</p><p>擅长密码学，安全分析，数字水印等技术。</p><p>你可以联系我通过:findmykexin@gmail.com或者知乎私信。</p><p>我的知乎链接：<a href=\"https://www.zhihu.com/people/su-chi-dan-dao\" rel=\"noopener noreferrer\" target=\"_blank\">苏迟但到 - 知乎 (zhihu.com)</a></p><p>我的github链接：<a href=\"https://github.com/kexinoh\" rel=\"noopener noreferrer\" target=\"_blank\">kexinoh</a></p>","icon":"https://kexohcdn.gptapi.cyou/kexohproject/production/images/channel-2e54d141ee195646ca12a9d16507a908.jpg","favicon":"https://kexohcdn.gptapi.cyou/kexohproject/production/images/favicon-340a2925d02a0386f3b954a032834917.jpg","authors":[{"name":"苏迟但到"}],"language":"zh-cn","items":[{"id":"GJnqWvFVQ-f","title":"如果想突破rsa算法，直接生成所有质数表，然后对应n是否可行?","content_html":"<p data-pid=\"BCIs9cTa\">其他答主还有一点没说，素数检验算法是多项式时间复杂度，RSA破解算法目前最优的是指数时间复杂度。</p><p data-pid=\"Z7nJ9QGZ\">自然可以生成很长的素数，但确不能分解。</p><p data-pid=\"ETjX31hm\">当然，构造超大素数还可以利用数学原理等等。</p><p></p>","content_text":"其他答主还有一点没说，素数检验算法是多项式时间复杂度，RSA破解算法目前最优的是指数时间复杂度。\n\n自然可以生成很长的素数，但确不能分解。\n\n当然，构造超大素数还可以利用数学原理等等。\n\n","date_published":"2023-01-21T07:56:43.000Z","_microfeed":{"web_url":"https://kexohproject.pages.dev/i/rsan-GJnqWvFVQ-f/","json_url":"https://kexohproject.pages.dev/i/GJnqWvFVQ-f/json/","rss_url":"https://kexohproject.pages.dev/i/GJnqWvFVQ-f/rss/","guid":"GJnqWvFVQ-f","status":"published","itunes:title":"New Article Title for iTunes","date_published_short":"Sat Jan 21 2023","date_published_ms":1674287803000}}],"_microfeed":{"microfeed_version":"0.1.2","base_url":"https://kexohproject.pages.dev","categories":[{"name":"Education","categories":[{"name":"Language Learning"}]},{"name":"Technology"}],"subscribe_methods":[{"name":"RSS","type":"rss","url":"https://kexohproject.pages.dev/rss/","image":"https://kexohproject.pages.dev/assets/brands/subscribe/rss.png","enabled":true,"editable":false,"id":"4KlfbtkEfzy"},{"name":"JSON","type":"json","url":"https://kexohproject.pages.dev/json/","image":"https://kexohproject.pages.dev/assets/brands/subscribe/json.png","enabled":true,"editable":false,"id":"DVFm7TYiNSq"}],"description_text":"你好，欢迎访问个人主页！\n\n擅长密码学，安全分析，数字水印等技术。\n\n你可以联系我通过:findmykexin@gmail.com或者知乎私信。\n\n我的知乎链接：苏迟但到 - 知乎 (zhihu.com)\n\n我的github链接：kexinoh","copyright":"©2024","itunes:type":"episodic","items_sort_order":"newest_first"}}