{"version":"https://jsonfeed.org/version/1.1","title":"苏迟但到的主页","home_page_url":"https://kexohproject.pages.dev","feed_url":"https://kexohproject.pages.dev/json/","description":"<p>你好，欢迎访问个人主页！</p><p>擅长密码学，安全分析，数字水印等技术。</p><p>你可以联系我通过:findmykexin@gmail.com或者知乎私信。</p><p>我的知乎链接：<a href=\"https://www.zhihu.com/people/su-chi-dan-dao\" rel=\"noopener noreferrer\" target=\"_blank\">苏迟但到 - 知乎 (zhihu.com)</a></p><p>我的github链接：<a href=\"https://github.com/kexinoh\" rel=\"noopener noreferrer\" target=\"_blank\">kexinoh</a></p>","icon":"https://kexohcdn.gptapi.cyou/kexohproject/production/images/channel-2e54d141ee195646ca12a9d16507a908.jpg","favicon":"https://kexohcdn.gptapi.cyou/kexohproject/production/images/favicon-340a2925d02a0386f3b954a032834917.jpg","authors":[{"name":"苏迟但到"}],"language":"zh-cn","items":[{"id":"OE4fhd8bjYQ","title":"1²＋2²＋……＋1005² 是奇数还是偶数？","content_html":"<p data-pid=\"o1CAQjDx\">对其就是mod2运算</p><p data-pid=\"GtHNA8tW\">因为1^2=1mod 2</p><p data-pid=\"A-UPgB2J\">0^2=0 mod2</p><p data-pid=\"9l_EZFHC\">所以原式子等于</p><p data-pid=\"1JG3eqqh\">1+0+1+0.....+1=503=1 mod 2</p><p data-pid=\"zAgj-XrB\">完</p>","content_text":"对其就是mod2运算\n\n因为1^2=1mod 2\n\n0^2=0 mod2\n\n所以原式子等于\n\n1+0+1+0.....+1=503=1 mod 2\n\n完","date_published":"2023-04-23T09:32:59.000Z","_microfeed":{"web_url":"https://kexohproject.pages.dev/i/121005-OE4fhd8bjYQ/","json_url":"https://kexohproject.pages.dev/i/OE4fhd8bjYQ/json/","rss_url":"https://kexohproject.pages.dev/i/OE4fhd8bjYQ/rss/","guid":"OE4fhd8bjYQ","status":"published","itunes:title":"New Article Title for iTunes","date_published_short":"Sun Apr 23 2023","date_published_ms":1682242379000}}],"_microfeed":{"microfeed_version":"0.1.2","base_url":"https://kexohproject.pages.dev","categories":[{"name":"Education","categories":[{"name":"Language Learning"}]},{"name":"Technology"}],"subscribe_methods":[{"name":"RSS","type":"rss","url":"https://kexohproject.pages.dev/rss/","image":"https://kexohproject.pages.dev/assets/brands/subscribe/rss.png","enabled":true,"editable":false,"id":"4KlfbtkEfzy"},{"name":"JSON","type":"json","url":"https://kexohproject.pages.dev/json/","image":"https://kexohproject.pages.dev/assets/brands/subscribe/json.png","enabled":true,"editable":false,"id":"DVFm7TYiNSq"}],"description_text":"你好，欢迎访问个人主页！\n\n擅长密码学，安全分析，数字水印等技术。\n\n你可以联系我通过:findmykexin@gmail.com或者知乎私信。\n\n我的知乎链接：苏迟但到 - 知乎 (zhihu.com)\n\n我的github链接：kexinoh","copyright":"©2024","itunes:type":"episodic","items_sort_order":"newest_first"}}